5(x+2)=3[x-(4-x)]

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Solution for 5(x+2)=3[x-(4-x)] equation:


Simplifying
5(x + 2) = 3[x + -1(4 + -1x)]

Reorder the terms:
5(2 + x) = 3[x + -1(4 + -1x)]
(2 * 5 + x * 5) = 3[x + -1(4 + -1x)]
(10 + 5x) = 3[x + -1(4 + -1x)]
10 + 5x = 3[x + (4 * -1 + -1x * -1)]
10 + 5x = 3[x + (-4 + 1x)]

Reorder the terms:
10 + 5x = 3[-4 + x + 1x]

Combine like terms: x + 1x = 2x
10 + 5x = 3[-4 + 2x]
10 + 5x = [-4 * 3 + 2x * 3]
10 + 5x = [-12 + 6x]

Solving
10 + 5x = -12 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
10 + 5x + -6x = -12 + 6x + -6x

Combine like terms: 5x + -6x = -1x
10 + -1x = -12 + 6x + -6x

Combine like terms: 6x + -6x = 0
10 + -1x = -12 + 0
10 + -1x = -12

Add '-10' to each side of the equation.
10 + -10 + -1x = -12 + -10

Combine like terms: 10 + -10 = 0
0 + -1x = -12 + -10
-1x = -12 + -10

Combine like terms: -12 + -10 = -22
-1x = -22

Divide each side by '-1'.
x = 22

Simplifying
x = 22

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